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A positive exponent tells you how many times to multiply the base number by itself. For example, the exponential term y3 is the same as y × y × y, or y multiplied by itself twice. Once you’ve grasped that basic concept, you can start to add on extra layers like negative exponents, fractional exponents or even a combination of both.
A negative, fractional exponent _y_ −_m_/_n_ can be factored to the form:
1 / (_n_√_y_)_m_
Before factoring negative, fractional exponents, let’s take a quick look at how to factor negative exponents, or negative powers, in general. A negative exponent does exactly the inverse of a positive exponent. So while a positive exponent like a4 tells you to multiply a by itself three times (so there are four in total in the expression), or a × a × a × a, seeing a negative exponent tells you to divide by a four times: so
(a^{-4} = frac{1}{a × a × a × a})
Or, to put it more formally:
(x^{-y} = frac{1}{x^y})
The next step is learning how to factor fractional exponents. Let’s start with a very simple fractional exponent, such as x1/y. When you see a fractional exponent like this, it means you must take the yth root of the base number. To put it more formally:
(x^{1/y} = sqrt[y]{x})
If that seems confusing, a few more concrete examples can help:
(y^{1/3} = sqrt[3]{y})(b^{1/2 }= sqrt{b})
(Remember, √x is the same as 2√x; but this expression is so common that the 2, or index number, is omitted.)
(8^{1/3} = sqrt[3]{8 }= 2)
What if the numerator of the fractional exponent isn’t 1? Then that number’s value remains as an exponent, applied to the entire “root” term. In formal terms, that means:
(y^{m/n} = (sqrt[n]{y})^m)
As a more concrete example, consider this:
(a^{b/5} = (sqrt[5]{a})^b)
When it comes to factoring negative fractional exponents, you can combine what you’ve learned about factoring expressions with negative exponents and those with fractional exponents.
Remember,
(x^{-y} = frac{1}{x^y})
regardless of what’s in the y spot; y could even be a fraction.
So if you have an expression x −a/b, that’s equal to 1/(_xa_/b). But you can simplify a step further by also applying what you know about fractional exponents to the term in the denominator of the fraction.
Remember,
(y^{m/n} = (sqrt[n]{y})^m)
or, to use the variables you’re already dealing with,
(x^{a/b} = (sqrt[b]{x})^a)
So, going that further step in simplifying x −a/b, you have
(x^{-a/b} = frac{1}{x^{a/b}} = frac{1}{(sqrt[b]{x})^a})
That’s as far as you can simplify without knowing more about x, b or a. But if you do know more about any of those terms, you might be able to simplify further.
To illustrate that, here’s one more example with a bit more information added:
Simplify
(16^{-4/8})
First, did you notice that −4/8 can be reduced to −1/2? So you have 16 −1/2, which already looks a lot friendlier (and maybe even more familiar) than the original problem.
Simplifying as before, you’ll arrive at
(16^{-1/2} = frac{1}{(sqrt[2]{16})^1})
which is usually written simply as
(frac{1}{sqrt{16}})
And since you know (or can quickly calculate) that √16 = 4, you can simplify that one last step to:
(16^{-4/8} = frac{1}{4})