Physical Address
Suite 5, 181 High Street,
Willoughby North NSW 2068
Physical Address
Suite 5, 181 High Street,
Willoughby North NSW 2068
A third power polynomial, also called a cubic polynomial, includes at least one monomial or term that is cubed, or raised to the third power. An example of a third power polynomial is
(4x^3-18x^2-10x)
To learn how to factor these polynomials, begin by getting comfortable with three different factoring scenarios: sum of two cubes, difference of two cubes and trinomials. Then move on to more complicated equations, such as polynomials with four or more terms. Factoring a polynomial requires breaking down the equation into pieces (factors) that when multiplied will yield back the original equation.
Use the standard formula
(a^3+b^3=(a+b)(a^2-ab+b^2))
when factoring an equation with one cubed term added to another cubed term, such as x3+ 8.
Determine what represents a in the equation. In the example x3+ 8, x represents a, since x is the cube root of x3.
Determine what represents b in the equation. In the example, x3+8, b3 is represented by 8; thus, b is represented by 2, since 2 is the cube root of 8.
Factor the polynomial by filling in the values of a and b into the solution
((a+b)(a^2-ab+b^2))
If a = x and b = 2, then the solution is
((x + 2)(x^2- 2x + 4))
Solve a more complicated equation using the same methodology. For example, solve
(64y^3+27)
Determine that 4y represents a and 3 represents b. The solution is
((4y+3)(16y^2-12y+9))
Use the standard formula
(a^3-b^3=(a-b)(a^2+ab+b^2))
when factoring an equation with one cubed term subtracting another cubed term, such as
(125x^3-1)
Determine what represents a in the polynomial. In 125x3 − 1, 5x represents a, since 5x is the cube root of 125x3.
Determine what represents b in the polynomial. In 125x3 − 1, 1 is the cube root of 1, thus b = 1.
Fill in the a and b values into the factoring solution
((a-b)(a^2+ab+b^2))
If a = 5x and b = 1, the solution becomes
((5x-1)(25x^2+5x+1))
Factor a third power trinomial (a polynomial with three terms) such as
(x^3+5x^2+6x)
Think of a monomial that is a factor of each of the terms in the equation. In
(x^3+5x^2+6x)
x is a common factor for each of the terms. Place the common factor outside of a pair of brackets. Divide each term of the original equation by x and place the solution inside the brackets:
(x(x^2+5x+6))
Mathematically, x3 divided by x equals x2, 5x2 divided by x equals 5x and 6x divided by x equals 6.
Factor the polynomial inside the brackets. In the example problem, the polynomial is
((x^2+5x+6))
Think of all the factors of 6, the last term of the polynomial. The factors of 6 equal 2 × 3 and 1 × 6.
Note the center term of the polynomial inside the brackets – 5x in this case. Select the factors of 6 that add up to 5, the coefficient of the central term. 2 and 3 add up to 5.
Write two sets of brackets. Place x at the beginning of each bracket followed by an addition sign. Next to one addition sign write down the first selected factor (2). Next to the second addition sign write the second factor (3). It should look like this:
((x+3)(x+2))
Remember the original common factor (x) to write the complete solution:
(x(x+3)(x+2))